Integrand size = 22, antiderivative size = 99 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {b^2 x^2}{2 d^3}+\frac {c (b c-a d)^2}{4 d^4 \left (c+d x^2\right )^2}-\frac {(b c-a d) (3 b c-a d)}{2 d^4 \left (c+d x^2\right )}-\frac {b (3 b c-2 a d) \log \left (c+d x^2\right )}{2 d^4} \]
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Time = 0.08 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {457, 78} \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {c (b c-a d)^2}{4 d^4 \left (c+d x^2\right )^2}-\frac {(3 b c-a d) (b c-a d)}{2 d^4 \left (c+d x^2\right )}-\frac {b (3 b c-2 a d) \log \left (c+d x^2\right )}{2 d^4}+\frac {b^2 x^2}{2 d^3} \]
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Rule 78
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x (a+b x)^2}{(c+d x)^3} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (\frac {b^2}{d^3}-\frac {c (b c-a d)^2}{d^3 (c+d x)^3}+\frac {(b c-a d) (3 b c-a d)}{d^3 (c+d x)^2}-\frac {b (3 b c-2 a d)}{d^3 (c+d x)}\right ) \, dx,x,x^2\right ) \\ & = \frac {b^2 x^2}{2 d^3}+\frac {c (b c-a d)^2}{4 d^4 \left (c+d x^2\right )^2}-\frac {(b c-a d) (3 b c-a d)}{2 d^4 \left (c+d x^2\right )}-\frac {b (3 b c-2 a d) \log \left (c+d x^2\right )}{2 d^4} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.15 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {-a^2 d^2 \left (c+2 d x^2\right )+2 a b c d \left (3 c+4 d x^2\right )+b^2 \left (-5 c^3-4 c^2 d x^2+4 c d^2 x^4+2 d^3 x^6\right )-2 b (3 b c-2 a d) \left (c+d x^2\right )^2 \log \left (c+d x^2\right )}{4 d^4 \left (c+d x^2\right )^2} \]
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Time = 2.66 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.06
method | result | size |
norman | \(\frac {\frac {b^{2} x^{6}}{2 d}-\frac {c \left (a^{2} d^{2}-6 a b c d +9 b^{2} c^{2}\right )}{4 d^{4}}-\frac {\left (a^{2} d^{2}-4 a b c d +6 b^{2} c^{2}\right ) x^{2}}{2 d^{3}}}{\left (d \,x^{2}+c \right )^{2}}+\frac {b \left (2 a d -3 b c \right ) \ln \left (d \,x^{2}+c \right )}{2 d^{4}}\) | \(105\) |
default | \(\frac {b^{2} x^{2}}{2 d^{3}}+\frac {\frac {c \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}{2 d \left (d \,x^{2}+c \right )^{2}}+\frac {b \left (2 a d -3 b c \right ) \ln \left (d \,x^{2}+c \right )}{d}-\frac {a^{2} d^{2}-4 a b c d +3 b^{2} c^{2}}{d \left (d \,x^{2}+c \right )}}{2 d^{3}}\) | \(113\) |
risch | \(\frac {b^{2} x^{2}}{2 d^{3}}+\frac {\left (-\frac {1}{2} a^{2} d^{2}+2 a b c d -\frac {3}{2} b^{2} c^{2}\right ) x^{2}-\frac {c \left (a^{2} d^{2}-6 a b c d +5 b^{2} c^{2}\right )}{4 d}}{d^{3} \left (d \,x^{2}+c \right )^{2}}+\frac {b \ln \left (d \,x^{2}+c \right ) a}{d^{3}}-\frac {3 b^{2} \ln \left (d \,x^{2}+c \right ) c}{2 d^{4}}\) | \(113\) |
parallelrisch | \(\frac {2 b^{2} d^{3} x^{6}+4 \ln \left (d \,x^{2}+c \right ) x^{4} a b \,d^{3}-6 \ln \left (d \,x^{2}+c \right ) x^{4} b^{2} c \,d^{2}+8 \ln \left (d \,x^{2}+c \right ) x^{2} a b c \,d^{2}-12 \ln \left (d \,x^{2}+c \right ) x^{2} b^{2} c^{2} d -2 x^{2} a^{2} d^{3}+8 x^{2} a b c \,d^{2}-12 x^{2} b^{2} c^{2} d +4 \ln \left (d \,x^{2}+c \right ) a b \,c^{2} d -6 \ln \left (d \,x^{2}+c \right ) b^{2} c^{3}-c \,a^{2} d^{2}+6 a b \,c^{2} d -9 b^{2} c^{3}}{4 d^{4} \left (d \,x^{2}+c \right )^{2}}\) | \(195\) |
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Time = 0.24 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.80 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {2 \, b^{2} d^{3} x^{6} + 4 \, b^{2} c d^{2} x^{4} - 5 \, b^{2} c^{3} + 6 \, a b c^{2} d - a^{2} c d^{2} - 2 \, {\left (2 \, b^{2} c^{2} d - 4 \, a b c d^{2} + a^{2} d^{3}\right )} x^{2} - 2 \, {\left (3 \, b^{2} c^{3} - 2 \, a b c^{2} d + {\left (3 \, b^{2} c d^{2} - 2 \, a b d^{3}\right )} x^{4} + 2 \, {\left (3 \, b^{2} c^{2} d - 2 \, a b c d^{2}\right )} x^{2}\right )} \log \left (d x^{2} + c\right )}{4 \, {\left (d^{6} x^{4} + 2 \, c d^{5} x^{2} + c^{2} d^{4}\right )}} \]
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Time = 3.57 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.23 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {b^{2} x^{2}}{2 d^{3}} + \frac {b \left (2 a d - 3 b c\right ) \log {\left (c + d x^{2} \right )}}{2 d^{4}} + \frac {- a^{2} c d^{2} + 6 a b c^{2} d - 5 b^{2} c^{3} + x^{2} \left (- 2 a^{2} d^{3} + 8 a b c d^{2} - 6 b^{2} c^{2} d\right )}{4 c^{2} d^{4} + 8 c d^{5} x^{2} + 4 d^{6} x^{4}} \]
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Time = 0.21 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.21 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {b^{2} x^{2}}{2 \, d^{3}} - \frac {5 \, b^{2} c^{3} - 6 \, a b c^{2} d + a^{2} c d^{2} + 2 \, {\left (3 \, b^{2} c^{2} d - 4 \, a b c d^{2} + a^{2} d^{3}\right )} x^{2}}{4 \, {\left (d^{6} x^{4} + 2 \, c d^{5} x^{2} + c^{2} d^{4}\right )}} - \frac {{\left (3 \, b^{2} c - 2 \, a b d\right )} \log \left (d x^{2} + c\right )}{2 \, d^{4}} \]
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Time = 0.30 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.08 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {b^{2} x^{2}}{2 \, d^{3}} - \frac {{\left (3 \, b^{2} c - 2 \, a b d\right )} \log \left ({\left | d x^{2} + c \right |}\right )}{2 \, d^{4}} - \frac {5 \, b^{2} c^{3} - 6 \, a b c^{2} d + a^{2} c d^{2} + 2 \, {\left (3 \, b^{2} c^{2} d - 4 \, a b c d^{2} + a^{2} d^{3}\right )} x^{2}}{4 \, {\left (d x^{2} + c\right )}^{2} d^{4}} \]
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Time = 5.07 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.24 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^3} \, dx=\frac {b^2\,x^2}{2\,d^3}-\frac {\ln \left (d\,x^2+c\right )\,\left (3\,b^2\,c-2\,a\,b\,d\right )}{2\,d^4}-\frac {x^2\,\left (\frac {a^2\,d^2}{2}-2\,a\,b\,c\,d+\frac {3\,b^2\,c^2}{2}\right )+\frac {a^2\,c\,d^2-6\,a\,b\,c^2\,d+5\,b^2\,c^3}{4\,d}}{c^2\,d^3+2\,c\,d^4\,x^2+d^5\,x^4} \]
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